How the Gravitational Red Shift Can Power the Fast Solar Wind
This is a supplementary article. To go to the main introductory article about Stationary Energy Theory, and its links to other supplementary articles, please click here.
I am going to show you how the energy lost from the gravitational red shift of light coming from the photosphere of the sun is sufficient to power all of the fast solar wind. The mechanism for how this would happen is a prediction of a new theory of cosmology and gravity that I have developed, which also correctly predicts the speeds of the solar wind, its composition, and the ratio of matter lost through the solar wind to the matter converted to energy in fusion reactions. You can read about this overall theory by clicking here. Meanwhile, I will show you the math pertaining these aspects of the gravitational red shift powering the solar wind.
Since the red shift at the surface of the Sun is Z = 2.12239 x 10-6, and energy is proportional to frequency, then the total energy lost in the gravitational red shift when a particle of mass m, such as a proton is converted to energy is:
E = Z x mc2. For reasons dictated by my new gravitational theory, only half this energy loss can be converted to kinetic energy in a particle of the solar wind. So we get KE = Z x ½mc2. The speed of this solar wind particle will be much lower than the speed of light, of course, because Z is such a small number. Its speed can be calculated by equating the energies:
½mwv2 = Z x ½mcc2
where mw is the mass of the solar wind particle, and mc is the mass of the particle(s) being converted to EMR by fusion reactions. So,
v2 = Zc2mc/mw
v = cZ½(mc/mw)½